1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
|
#!/bin/bash
#command line => CEPH_BRANCH=<branch>; MACHINE_NAME=<machine_type>; SUITE_NAME=<suite>; ../schedule_subset.sh <day_of_week> $CEPH_BRANCH $MACHINE_NAME $SUITE_NAME $CEPH_QA_EMAIL
# $1 - part (day of week)
# $2 - branch name
# $3 - machine name
# $4 - suite name
# $5 - email address
# $6 - filter out (this arg is to be at the end of the command line for now)
## example #1
## (date +%U) week number
## % 2 - mod 2 (e.g. 0,1,0,1 ...)
## * 7 - multiplied by 7 (e.g. 0,7,0,7...)
## $1 day of the week (0-6)
## /14 for 2 weeks
## example #2
## (date +%U) week number
## % 4 - mod 4 (e.g. 0,1,2,3,0,1,2,3 ...)
## * 7 - multiplied by 7 (e.g. 0,7,14,21,0,7,14,21...)
## $1 day of the week (0-6)
## /28 for 4 weeks
echo "Scheduling " $2 " branch"
if [ $2 = "master" ] ; then
# run master branch with --newest option looking for good sha1 7 builds back with /999 jobs
teuthology-suite -v -c $2 -m $3 -k distro -s $4 --subset $(echo "(($(date +%U) % 4) * 7) + $1" | bc)/999 --newest 7 -e $5 $6
elif [ $2 = "hammer" ] ; then
# run hammer branch with less jobs
teuthology-suite -v -c $2 -m $3 -k distro -s $4 --subset $(echo "(($(date +%U) % 4) * 7) + $1" | bc)/56 -e $5 $6
elif [ $2 = "jewel" ] ; then
# run jewel branch with /40 jobs
teuthology-suite -v -c $2 -m $3 -k distro -s $4 --subset $(echo "(($(date +%U) % 4) * 7) + $1" | bc)/40 -e $5 $6
elif [ $2 = "kraken" ] ; then
# run kraken branch with /999 jobs
teuthology-suite -v -c $2 -m $3 -k distro -s $4 --subset $(echo "(($(date +%U) % 4) * 7) + $1" | bc)/999 -e $5 $6
elif [ $2 = "luminous" ] ; then
# run luminous branch with /999 jobs
teuthology-suite -v -c $2 -m $3 -k distro -s $4 --subset $(echo "(($(date +%U) % 4) * 7) + $1" | bc)/999 -e $5 $6
else
# run NON master branches without --newest
teuthology-suite -v -c $2 -m $3 -k distro -s $4 --subset $(echo "(($(date +%U) % 4) * 7) + $1" | bc)/28 -e $5 $6
fi
|
