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#!/bin/bash

cd /bottlenecks/rubbos/rubbos_scripts/1-1-1
source set_bottlenecks_rubbos_env.sh
cd -

# delay inbetween snapshots

delay=1

# central host to send results to
analysis_host=$BENCHMARK_HOST

# monitoring start/end time in format YYYYmmddHHMMSS (20050920152059)
start_time=$1
end_time=$2

# data filename suffix
data_filename_suffix="`hostname`-${start_time}.data"

# sar filename
sar_filename=$RUBBOS_APP/sar-${data_filename_suffix}

# iostat filename
iostat_filename=$RUBBOS_APP/iostat-${data_filename_suffix}

# ps filename
ps_filename=$RUBBOS_APP/ps-${data_filename_suffix}

# date command in predefined format
date_cmd="date +%Y%m%d%H%M%S"
date=`$date_cmd`

# TEST MODE: start_time will be 2 seconds from launch, end time 5 seconds
#start_time=`expr $date \+ 2`
#end_time=`expr $date \+ 5`

#echo
#echo Current timestamp:  $date
#echo Start timestamp:  $start_time
#echo End timestamp:  $end_time
#echo

# make sure they have all arguments
if [ "$end_time" = "" ]; then
  echo usage: $0 \<delay\> \<analysis host\> \<start time\> \<end time\>
  echo start_time and end_time are in YYYYmmddHHMMSS format
  echo ie: 9/30/2005, 2:31:54pm = 20050930143154
  echo
  exit
fi

# wait until start time
#echo -n Waiting until start time \(${start_time}\)..
date=`$date_cmd`
while [ $date -lt $start_time ]; do
  sleep 1
  date=`$date_cmd`
done
#echo


# launch iostat
sudo nice -n -1 $SYSSTAT_HOME/bin/iostat -dxtk $delay > ${iostat_filename} &
iostat_pid=$!


# run test until end time
#echo -n Running test until end time \(${end_time}\)..
while [ $date -lt $end_time ]; do

  sleep $delay
  date=`$date_cmd`
done
#echo


# kill iostat
sudo kill -9 $iostat_pid


# chmod

sudo chmod g+w ${iostat_filename}
sudo chmod o+r ${iostat_filename}


# send data to analysis host
#echo Sending data to analysis host.. 
#scp -o StrictHostKeyChecking=no -o BatchMode=yes ${sar_filename} ${analysis_host}:/tmp/elba/rubbos
#scp -o StrictHostKeyChecking=no -o BatchMode=yes ${ps_filename} ${analysis_host}:/tmp/elba/rubbos
"nx">k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right) </script> </section> <section> <h3>A Cross Product Formula</h3> \[\mathbf{V}_1 \times \mathbf{V}_2 = \begin{vmatrix} \mathbf{i} &amp; \mathbf{j} &amp; \mathbf{k} \\ \frac{\partial X}{\partial u} &amp; \frac{\partial Y}{\partial u} &amp; 0 \\ \frac{\partial X}{\partial v} &amp; \frac{\partial Y}{\partial v} &amp; 0 \end{vmatrix} \] </section> <section> <h3>The probability of getting \(k\) heads when flipping \(n\) coins is</h3> \[P(E) = {n \choose k} p^k (1-p)^{ n-k} \] </section> <section> <h3>An Identity of Ramanujan</h3> \[ \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\ldots} } } } \] </section> <section> <h3>A Rogers-Ramanujan Identity</h3> \[ 1 + \frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots = \prod_{j=0}^{\infty}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})}\] </section> <section> <h3>Maxwell&#8217;s Equations</h3> \[ \begin{aligned} \nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t} &amp; = \frac{4\pi}{c}\vec{\mathbf{j}} \\ \nabla \cdot \vec{\mathbf{E}} &amp; = 4 \pi \rho \\ \nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} &amp; = \vec{\mathbf{0}} \\ \nabla \cdot \vec{\mathbf{B}} &amp; = 0 \end{aligned} \] </section> <section> <section> <h3>The Lorenz Equations</h3> <div class="fragment"> \[\begin{aligned} \dot{x} &amp; = \sigma(y-x) \\ \dot{y} &amp; = \rho x - y - xz \\ \dot{z} &amp; = -\beta z + xy \end{aligned} \] </div> </section> <section> <h3>The Cauchy-Schwarz Inequality</h3> <div class="fragment"> \[ \left( \sum_{k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right) \] </div> </section> <section> <h3>A Cross Product Formula</h3> <div class="fragment"> \[\mathbf{V}_1 \times \mathbf{V}_2 = \begin{vmatrix} \mathbf{i} &amp; \mathbf{j} &amp; \mathbf{k} \\ \frac{\partial X}{\partial u} &amp; \frac{\partial Y}{\partial u} &amp; 0 \\ \frac{\partial X}{\partial v} &amp; \frac{\partial Y}{\partial v} &amp; 0 \end{vmatrix} \] </div> </section> <section> <h3>The probability of getting \(k\) heads when flipping \(n\) coins is</h3> <div class="fragment"> \[P(E) = {n \choose k} p^k (1-p)^{ n-k} \] </div> </section> <section> <h3>An Identity of Ramanujan</h3> <div class="fragment"> \[ \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\ldots} } } } \] </div> </section> <section> <h3>A Rogers-Ramanujan Identity</h3> <div class="fragment"> \[ 1 + \frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots = \prod_{j=0}^{\infty}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})}\] </div> </section> <section> <h3>Maxwell&#8217;s Equations</h3> <div class="fragment"> \[ \begin{aligned} \nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t} &amp; = \frac{4\pi}{c}\vec{\mathbf{j}} \\ \nabla \cdot \vec{\mathbf{E}} &amp; = 4 \pi \rho \\ \nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} &amp; = \vec{\mathbf{0}} \\ \nabla \cdot \vec{\mathbf{B}} &amp; = 0 \end{aligned} \] </div> </section> </section> </div> </div> <script src="../../lib/js/head.min.js"></script> <script src="../../js/reveal.js"></script> <script> Reveal.initialize({ history: true, transition: 'linear', math: { // mathjax: 'http://cdn.mathjax.org/mathjax/latest/MathJax.js', config: 'TeX-AMS_HTML-full' }, dependencies: [ { src: '../../lib/js/classList.js' }, { src: '../../plugin/math/math.js', async: true } ] }); </script> </body> </html>